Stoichiometry ... Can You Make 2.00 Grams of a Compound ? Essay

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Stoichiometry ... Can You Make 2.00 Grams of a Compound ? This lab is based on calculating molar mass, balancing equations, and predicting the chemical reactions that take place in complex stoichiometry problems.Stoichiometry is the study of the quantitative relationship in a chemical equation and is the basis of the lab.Molar mass is the mass, in grams, of a single mole of a substance. This problem's starting substance, or reactant, is CaCl22H20 and K2CO3. Once the lab is completed, approximately 2.00g of CaCo3, the precipitate, should remain. The precipitate is the solid that seperates from the solution during the chemical reaction. This problem is a double displacement problem : it is a compound plus a compound that yields another compound plus a compound. If Some topics in this essay: Mass Reactant, Chloride Dihydrate, Percent Error, CaCl22H20 K2CO3, , Mass H2O, Goggles Methods, Potassium Carbonate, 1 mol, caco3 1, caco3 1 mol, 200g caco3, mol caco3, 1 mol caco3, Metal Ring, mol caco3 1, Graduated Cylinder, 100g caco3, reactant 200g, = 100g, mass reactant, 100g caco3 1, 200g caco3 1, 150ml beaker, 294g cacl2*2h2o, Join now to see the rest of the essay! Approximate Word count = 491 Approximate Pages = 2 (250 words per page double spaced)
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