This amount was compared to the accepted value to find percent difference.
Data: See attachments: Table 8.1 Specific Heat Capacity Data and Calculations and Table 8.2: Latent Heat Data and Calculations.
Analysis: For case number one of specific heat capacity the initial temperature of the iron was 100 degrees Celsius. The temperature that was read for the temperature of the tap water was 21.7 degrees Celsius. This value is our initial water temperature. After placing the 100-gram iron in the calorimeter, we waited for the iron to transfer its heat. The final temperature was calculated at 25.9 degrees Celsius. The measurement for the mass of the cup and the water was found to be 199.14 grams. We took this calculation and subtracted the 12.1 grams from the cup and found the mass of the water to be 187.04 grams. From these values, the specific heat capacity for case number one was found to be .106 (cal)/(g Celsius) from the formula:.
c(iron) = c(water)m(water)(Tf-Twater).
m(iron)(Tiron-Tf).
This formula is derived by setting the two formulas for the heat lost by the iron sphere and the heat gained by the water equal to each other. The formulas are:.
.
Qlost = c(lost)m(lost)(Tiron-Tf) Qgained = c(water)m(water)(Tiron-Tf).
For trial two the specific heat capacity was found to be .113(cal)/(g Celsius) and for trial three the specific heat capacity was found to be .115 (cal)/(g Celsius). The same formula stated above was used but with different variables of initial water, final water, and mass variables.
Next we calculated our average value of specific heat capacity by taking the sum of our three trials and dividing by three. The average was .111 (cal)/(g Celsius). The accepted value was .105 (cal)/(g Celsius). When taking the percent difference we used the formula (average-accepted)/(accepted) and came up with a value of 5.7%.
For latent heat calculations, we again did three trials. In the first trial the initial temperature of the water was found to be 22.