This lab is based on calculating molar mass, balancing equations, and predicting the chemical reactions that take place in complex stoichiometry problems.Stoichiometry is the study of the quantitative relationship in a chemical equation and is the basis of the lab.Molar mass is the mass, in grams, of a single mole of a substance. This problem's starting substance, or reactant, is CaCl2*2H20 and K2CO3. Once the lab is completed, approximately 2.00g of CaCo3, the precipitate, should remain. The precipitate is the solid that seperates from the solution during the chemical reaction. This problem is a double displacement problem : it is a compound plus a compound that yields another compound plus a compound. If 2.94g of CaCl2*2H2O is mixed with 2.76g of K2CO3, then 2.00g of CaCO3, the precipitate, will be formed. .
50mL Beaker (2).
50mL Graduated Cylinder.
150mL Beaker .
2.76g of Potassium Carbonate.
2.94g of Calcium Chloride Dihydrate.
Filter Paper (2).
1.) Put on apron and goggles for safety purposes.
2.) Write a balnced equation with the 2 given reactants.
3.) Place the balance at 0 and measure the paper filter.
4.) Measure 2.76g of Potassium Carbonate, put in a 50mL beaker, and mix.
with 50mL of water until completely dissolved.
5.) Measure 2.94g of Calcium Chloride Dihydrate, put in a 50mL beaker, and.
mix with 50mL of water until dissolved.
6.) Combine the 2 compounds together in a 150mL beaker. Stir until.
7.) Calculate the mass of the second filter paper and record the data. Place .
filter into funnel.
8.) Pour the compounds of the 150mL beaker into the funnel and allow the .
contents to drain into the 250mL beaker.
9.) Allow precipitate to sit over night.
10.) After precipitate has thoroughly drained, measure the remaining contents.