# Usage of Gaseous Fuel in Vehicles

As an introduction to for usage of gaseous fuels in vehicles , i would like to mention some alternative fuels under some headlines listed below ; and if we want to compare liquid and gaseous fuels , we do have to have some stable parameters.These parameters are ;.

• Storage.

• Design (The Design of the vehicle according to the fuel that is used).

• Price.

• Environment .

• Safety.
When we especially focus on the design of the vehicle , Fuel Tank is seem to be the one of the most important part of the vehicle.Fuel Tank has an importance with ;.

• The size and the weight of it.

• The material that it's made of.

• The temperature limits of the tank.

• The pressure necessary for the storage of the fuel in the tank.
Additionally , if we want to compare fuels for vehicles , vehicles must have ; .

• Same Power.

• Same Autonomy.

• Same Utilizable Volume.
I would like to also mention some calculation to find out that How many liters LPG and natural gas do we need for the same efficient energy that is provided by 30 lt. of gasoline?.
For 30 lt. Gasoline Tank.
The lower calorific volume.
10.000 kcal/kg x 30 x 0.85 = 255.000 kcal.
Efficiency of gasoline = 35%.
Thus.
Efficient energy.
0,35 x 255.000 = 89.250 kcal.
(The efficient energy of 30 lt.=25,5 Kg gasoline).
For LPG The Efficiency = 32%.
LCV (Lower Calorific Volume) = 89.250/0.32 = 278.907 kcal.
1 kg 11.000.
X 278.907.
X = 25.36 kg LPG = 51 lt.
So we need 51lt. LPG for the same energy that we provide from 30 lt. gasoline. .
For Natural Gas.
For natural gas.
8250 kcal/m3 1atm 15oC.
The efficiency for LPG = 32% = 278.907 kcal.
n = 1 x 1000 / 0.082 x (273 + 15).
n = 42 mols.
42 mol 8250 kcal.
X 278.907 kcal .
X = 1420 molCH4.
200 atm (Approximate pressure).
77oC (Probable temperature of fuel tank(upper degree)).
77 + 273 = 350 K.
P x V = N x R x T.

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