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# Chemistry Lab - Leftover Aluminum Wire

We were able to ignore the terms on the right side of the equation because we know mass is conserved within the reaction. Also the conservation of atoms tells us that the ratio of moles of copper chloride to aluminum is constant. So given the amount of copper chloride that reacted, we could find the amount of aluminum that reacted. If all the aluminum dissolved and the liquid was still blue, we would know that aluminum was the limiting reagent. We would also be able to calculate the mass of the original aluminum wire if we were able to measure the mass of the leftover copper. By finding the mass of the copper, we can find the mass of the amount of copper chloride that reacted then from the process from question 1, we can find the mass of the original aluminum wire. From the compound, CuCl2, we know that Cu is positively charged and Cl is negatively charged. When put in the water, the water allows the molecules to flow freely which puts it closer to the aluminum. Since aluminum has a greater positive charge than copper, the chloride, being a negative, moves to the aluminum and reacts with it creating aluminum chloride.
We were able to ignore the terms on the right side of the equation because we know mass is conserved within the reaction. Also the conservation of atoms tells us that the ratio of moles of copper chloride to aluminum is constant. So given the amount of copper chloride that reacted, we could find the amount of aluminum that reacted. If all the aluminum dissolved and the liquid was still blue, we would know that aluminum was the limiting reagent. We would also be able to calculate the mass of the original aluminum wire if we were able to measure the mass of the leftover copper. By finding the mass of the copper, we can find the mass of the amount of copper chloride that reacted then from the process from question 1, we can find the mass of the original aluminum wire.

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